Question 1

What will happen when you attempt to compile and run the code below, assuming that you

enter the following sequence: 1 2 3 end<enter>?

#include <iostream>

#include <string>

#include <list>

#include <algorithm>

using namespace std;

template<class T>struct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) {out<<val<<" "; } };

int main ()

{

list<int> l;

for( ; !cin.bad() ; )

{

int i;

cin>>i;

l.push_back(i);

}

for_each(l.begin(), l.end(), Out<int>(cout));

return 0;

}

Program will output:

Options :

A : 1 2 3

B : 1 2 3 end

C : 1

D : compilation error

E : program runs forever without output

Answer: A

Question 2

What happens when you attempt to compile and run the following code?

#include <vector>

#include <iostream>

#include <algorithm>

using namespace std;

template<typename T>class B { T val;

public:

B(T v):val(v){}

T getV() const {return val;} bool operator < (const B & v) const { return val<v.val;} };

template<class T>ostream & operator <<(ostream & out, const B<T> & v) { out<<v.getV();

return out;}

template<class T>struct Out {

ostream & out;

Out(ostream & o): out(o){}void operator() (const T & val ) { out<<val<<" "; } };

bool Less(const B<float> &a, const B<float> &b) { return int(a.getV())<int(b.getV());}

int main() {

float t[]={2.28, 1.66, 1.32, 3.94, 3.64, 2.3, 2.98, 1.96, 2.62, 1.13};

vector<B<float> > v1; v1.assign(t, t+10);

stable_sort(v1.begin(), v1.end(), Less);

for_each(v1.begin(), v1.end(), Out<B<float> >(cout));cout<<endl;

return 0;

}

Program outputs:

Options :

A : 1.66 1.32 1.96 1.13 2.28 2.3 2.98 2.62 3.94 3.64

B : 1.13 1.32 1.66 1.96 2.28 2.3 2.62 2.98 3.64 3.94

C : compilation error

D : 3.94 3.64 2.98 2.62 2.3 2.28 1.96 1.66 1.32 1.13

E : the exact output is impossible to determine

Answer: A

Question 3

What happens when you attempt to compile and run the following code?

#include <deque>

#include <iostream>

#include <algorithm>

using namespace std;

template<class T>struct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<<val<<" "; } };

int main() {

int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3};

deque<int> d1(t, t+10);

sort(d1.begin(), d1.end());

deque<int>::iterator it = upper_bound(d1.begin(), d1.end(), 4);

for_each(it, d1.end(), Out<int>(cout));cout<<endl;

return 0;

}

Program outputs:

Options :

A : 5 6 7 8 9 10

B : 4 5 6 7 8 9 10

C : 1 2 3 4 5 6 7 8 9 10

D : 1 2 3 4 5

E : 1 2 3 4

Answer: A

Question 4

What happens when you attempt to compile and run the following code?

#include <vector>

#include <iostream>

#include <algorithm>

using namespace std;

class B { int val;

public:B(int v):val(v){}

int getV() const {return val;} bool operator < (const B & v) const { return val<v.val;} };

ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;}

template<class T>struct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<<val<<" "; } };

int main() {

B t1[]={3,2,4,1,5};

B t2[]={6,10,8,7,9};

vector<B> v1(10);

sort(t1, t1+5);

sort(t2, t2+5);

merge(t1,t1+5,t2,t2+5,v1.begin());

for_each(v1.begin(), v1.end(), Out<B>(cout));cout<<endl;

return 0;

}

Program outputs:

Options :

A : 1 2 3 4 5 6 10 8 7 9

B : 3 2 4 1 5 6 7 8 9 10

C : 3 2 4 1 5 6 10 8 7 9

D : 1 2 3 4 5 6 7 8 9 10

E : compilation error

Answer: A

Question 5

What happens when you attempt to compile and run the following code?

#include <iostream>

using namespace std;

int main ()

{

float f1 = 10.0;

float f2 = 10.123;

cout<<noshowpoint<<f1<<" "<<f2;

return 0;

}

Program outputs:

Options :

A : 10 10

B : 10.0 10.123

C : compilation error

D : 10 10.123

Answer: D